时针分针角度问题c语言解法

#include <stdio.h>

//时针一小时走30度

double hour_per_hour_angle = 30.0;

//先算出时针和分钟 一分钟内 分别走多少度数

//时针一分钟走0.5度

double hour_per_minite_angle = 0.5; //360/12/60

//分针一分钟走 6 度

double minite_per_minite_angle = 6.0; //360/12/5

int main()

{

    int hour, minite;

    while(scanf("%d:%d", &hour, &minite))

    {

        double hour_angle = (hour * hour_per_hour_angle + minite * hour_per_minite_angle);

        double minite_angle = (minite * minite_per_minite_angle);

        double angle =  hour_angle - minite_angle;

        printf("%f, %f, %f\n",hour_angle, minite_angle, angle);

        printf("%.1f\n", fabs(angle));

    }

    return 0;

}

时针分针角度问题c语言解法

原文：https://www.cnblogs.com/cute/p/11496299.html