题目:请实现两个函数,分别用来序列化和反序列化二叉树
/*
struct TreeNode {
int val;
struct TreeNode *left;
struct TreeNode *right;
TreeNode(int x) :
val(x), left(NULL), right(NULL) {
}
};
*/
class Solution {
public:
//序列化
void do_Serialize(TreeNode *root, string &s)
{
if(root == nullptr)
{
s += ‘#‘;
s += ‘,‘;
return;
}
//std::to_string() 数值转换字符串
s += to_string(root->val);
s += ‘,‘;
do_Serialize(root->left,s);
do_Serialize(root->right,s);
}
char* Serialize(TreeNode *root)
{
if(root == nullptr)
{
return nullptr;
}
string str = "";
do_Serialize(root,str);
//返回值是char *
char *ret = new char[str.length() + 1]; //‘\0‘
strcpy(ret, str.c_str());
return ret;
}
//反序列化
TreeNode* do_Deserialize(string &s)
{
if(s.empty())
{
return nullptr;
}
if (s[0] == ‘#‘)
{
s = s.substr(2); //从s中去掉#,
return nullptr;
}
TreeNode *ret = new TreeNode(stoi(s));
s = s.substr(s.find_first_of(‘,‘) + 1);
ret->left = do_Deserialize(s);
ret->right = do_Deserialize(s);
return ret;
}
TreeNode* Deserialize(char *str)
{
if(str == nullptr)
{
return nullptr;
}
string s(str);
return do_Deserialize(s);
}
};
原文:https://www.cnblogs.com/xiexinbei0318/p/11434628.html