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Populating Next Right Pointers in Each Node II

时间:2014-02-15 15:35:38      阅读:325      评论:0      收藏:0      [点我收藏+]

Follow up for problem "Populating Next Right Pointers in Each Node".

What if the given tree could be any binary tree? Would your previous solution still work?

Note:

  • You may only use constant extra space.

 

For example,
Given the following binary tree,

         1
       /        2    3
     / \        4   5    7

 

After calling your function, the tree should look like:

         1 -> NULL
       /        2 -> 3 -> NULL
     / \        4-> 5 -> 7 -> NULL

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/**
 * Definition for binary tree with next pointer.
 * public class TreeLinkNode {
 *     int val;
 *     TreeLinkNode left, right, next;
 *     TreeLinkNode(int x) { val = x; }
 * }
 */
public class Solution {
    public void connect(TreeLinkNode root) {
        if(root == null)
            return;
        
        TreeLinkNode p = root.next;
        while(p != null){
            if(p.left != null){
                p = p.left;
                break;
            }
            if(p.right != null){
                p = p.right;
                break;
            }
            p = p.next;
        }
        
        if(root.left != null){
            if(root.right == null)
                root.left.next = p;
            else
                root.left.next = root.right;
        }
        
        if(root.right != null){
            if(root.next == null)
                root.right.next = null;
            else
                root.right.next = p;
        }
        
        connect(root.right);
        connect(root.left);
    }
}
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Populating Next Right Pointers in Each Node II

原文:http://www.cnblogs.com/RazerLu/p/3550209.html

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