You‘re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb" Output: 3
Example 2:
Input: J = "z", S = "ZZ" Output: 0
Note:
S
and J
will consist of letters and have length at most 50.J
are distinctclass Solution { public int numJewelsInStones(String J, String S) { int output = 0; for(int i = 0 ; i < J.length(); i++){ char tmp = J.charAt(i); for(int j = 0; j<S.length();j++){ if(tmp == S.charAt(j)){ output++; } } } return output; } }
(Easy) Jewels and Stones LeetCode
原文:https://www.cnblogs.com/codingyangmao/p/11273280.html