100 10 20 100 10 50
Yes No
题意：水题吧，不够没做过的话就可能不会做吧
#include<iostream>
#include<cstdio>
#define pi 3.1415926
using namespace std;
int main()
{
double sum1,sum2;
double V1,V2,R;
double r;
while(scanf("%lf %lf %lf",&R,&V1,&V2)!=EOF)
{
sum1=sum2=0.0;
r=V1*R/V2;
sum1=(R-r)/V1;
sum2=(pi*R)/V2;
if(sum1<sum2)
puts("Yes");
else
puts("No");
}
return 0;
}
hdu 1593 find a way to escape,布布扣,bubuko.com
原文：http://blog.csdn.net/chaoyueziji123/article/details/38556357