1、题目描述
在一个排序的链表中,存在重复的结点,请删除该链表中重复的结点,重复的结点不保留,返回链表头指针。 例如,链表1->2->3->3->4->4->5 处理后为 1->2->5
2、代码实现
import java.util.HashMap;
public class Solution {
public ListNode deleteDuplication(ListNode pHead)
{
//1、临界值的判断:
if (pHead == null) {
return null;
}
HashMap<Integer, Integer> hashMap = new HashMap<>();
ListNode temp = pHead;
while (temp != null) {
if (hashMap.containsKey(temp.val) == true) {
hashMap.put(temp.val, hashMap.get(temp.val) + 1);
} else {
hashMap.put(temp.val, 1);
}
temp = temp.next;
}
temp = pHead;
ListNode newHead = new ListNode(-1);
ListNode NTemp = newHead;
while (temp != null) {
if (hashMap.get(temp.val) > 1) {
temp = temp.next;
} else {
NTemp.next = new ListNode(temp.val);
NTemp = NTemp.next;
temp = temp.next;
}
}
return newHead.next;
}
}
原文:https://www.cnblogs.com/BaoZiY/p/11183573.html