[LeetCode] 154. Find Minimum in Rotated Sorted Array II_Hard tag: not real binary search anymore

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e.,  [0,1,2,4,5,6,7] might become  [4,5,6,7,0,1,2]).

Find the minimum element.

The array may contain duplicates.

Example 1:

Input: [1,3,5]
Output: 1

Example 2:

Input: [2,2,2,0,1]
Output: 0

Note:

• This is a follow up problem to Find Minimum in Rotated Sorted Array.
• Would allow duplicates affect the run-time complexity? How and why?

这题是[LeetCode] 153. Find Minimum in Rotated Sorted Array_Medium tag: Binary Search的follow up，允许重复，但是如果重复数量太多，比如[2,2,2,2,2,2,2,0,2,2,2,2] 时间复杂度可能会上升到O(n)， 而且二分法不再实用，所以直接用暴力破解就好。

Code

class Solution:
    def findMinRotate(self, nums):
        ans = nums[0]
        for num in nums:
            ans = min(ans, num)
        return ans

[LeetCode] 154. Find Minimum in Rotated Sorted Array II_Hard tag: not real binary search anymore

原文：https://www.cnblogs.com/Johnsonxiong/p/11168353.html