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LeetCode 100. Same Tree

时间:2019-05-26 23:10:12      阅读:141      评论:0      收藏:0      [点我收藏+]

100. Same Tree

Given two binary trees, write a function to check if they are the same or not.

Two binary trees are considered the same if they are structurally identical and the nodes have the same value.

Example 1:

Input:     1         1
          / \       /          2   3     2   3

        [1,2,3],   [1,2,3]

Output: true

Example 2:

Input:     1         1
          /                    2             2

        [1,2],     [1,null,2]

Output: false

Example 3:

Input:     1         1
          / \       /          2   1     1   2

        [1,2,1],   [1,1,2]

Output: false
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if (p == NULL || q == NULL)
        {
            return (p == q);
        }
        
        return (p->val == q->val) && isSameTree(p->left, q->left) && isSameTree(p->right, q->right);
    }
};

 

LeetCode 100. Same Tree

原文:https://www.cnblogs.com/douzujun/p/10927977.html

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