就是一个多重背包可行性判断,范围不大的话也可以用母函数处理出所有的情况、
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
#include <climits>
#include <string>
#include <iostream>
#include <map>
#include <cstdlib>
#include <list>
#include <set>
#include <queue>
#include <stack>
using namespace std;
typedef long long LL;
const int maxn = 55;
const int maxv = 50 * 50 * 100 + 5;
int c1[maxv],c2[maxv];
int val[maxn],cnt[maxn],n;
int main() {
while(scanf("%d",&n),n >= 0) {
int sum = 0;
for(int i = 0;i < n;i++) {
scanf("%d%d",&val[i],&cnt[i]);
sum += val[i] * cnt[i];
}
memset(c1,0,sizeof(int) * sum);
memset(c2,0,sizeof(int) * sum);
c1[0] = 1;
for(int i = 0;i < n;i++) {
for(int j = 0;j <= cnt[i];j++) {
for(int k = 0;val[i] * j + k <= sum;k++) {
c2[val[i] * j + k] += c1[k];
}
}
for(int j = 0;j <= sum;j++) {
c1[j] = c2[j]; c2[j] = 0;
}
}
int mindelta = INT_MAX,a1 = 0,a2 = 0;
for(int i = 0;i <= sum;i++) if(c1[i]) {
int nowd = abs(2 * i - sum);
if(nowd < mindelta) {
mindelta = nowd;
a1 = max(i,sum - i);
a2 = sum - a1;
}
}
printf("%d %d\n",a1,a2);
}
return 0;
}
HDU 1171 Big Event in HDU 母函数,布布扣,bubuko.com
原文:http://www.cnblogs.com/rolight/p/3896705.html