In computer science, a heap is a specialized tree-based data structure that satisfies the heap property: if P is a parent node of C, then the key (the value) of P is either greater than or equal to (in a max heap) or less than or equal to (in a min heap) the key of C. A common implementation of a heap is the binary heap, in which the tree is a complete binary tree. (Quoted from Wikipedia at https://en.wikipedia.org/wiki/Heap_(data_structure))
Your job is to tell if a given complete binary tree is a heap.
Each input file contains one test case. For each case, the first line gives two positive integers: M (≤ 100), the number of trees to be tested; and N (1 < N ≤ 1,000), the number of keys in each tree, respectively. Then M lines follow, each contains N distinct integer keys (all in the range of int), which gives the level order traversal sequence of a complete binary tree.
For each given tree, print in a line Max Heap
if it is a max heap, or Min Heap
for a min heap, or Not Heap
if it is not a heap at all. Then in the next line print the tree‘s postorder traversal sequence. All the numbers are separated by a space, and there must no extra space at the beginning or the end of the line.
3 8
98 72 86 60 65 12 23 50
8 38 25 58 52 82 70 60
10 28 15 12 34 9 8 56
Max Heap 50 60 65 72 12 23 86 98 Min Heap 60 58 52 38 82 70 25 8 Not Heap 56 12 34 28 9 8 15 10
思路
计算每个序列的最大值和最小值,因为如果是大顶堆,则第一个元素一定是这个序列的最大值,如果是小顶堆,则
这个序列的第一个元素一定是最小值,根据计算出的最大、最小值,初步判断这是一个大顶堆还是一个小顶堆。然后再
根据层次遍历序列进行验证,看是否满足堆的条件。
#include<iostream> #include<string> #include<vector> #include<cmath> #include<algorithm> using namespace std; int judge(int a[],int n,int flag) { if(flag==-1) return -1; for(int i=1; i<=n/2; i++) { int j=2*i; if(j<n&&a[j]>a[j+1]) j++; if(flag==1&&j<=n&&a[i]<a[j]) return -1; else if(flag==0&&j<=n&&a[i]>a[j]) return -1; } return flag; } vector<int> result; void postOrder(int a[],int n,int root) { if(root>n) return; postOrder(a,n,2*root); postOrder(a,n,2*root+1); result.push_back(a[root]); } int main() { int m,n; scanf("%d%d",&m,&n); for(int i=0; i<m; i++) { int a[n+1],maxV=-10000,minV=10000,flag; for(int i=1; i<n+1; i++) { scanf("%d",&a[i]); minV=min(a[i],minV); maxV=max(a[i],maxV); } if(a[1]==maxV) flag=1; else if(a[1]==minV) flag=0; else { flag=-1; } flag=judge(a,n,flag); if(flag==1) { printf("Max Heap\n"); } else if(flag==0) { printf("Min Heap\n"); } else { printf("Not Heap\n"); } result.clear(); postOrder(a,n,1); printf("%d",result[0]); for(int i=1; i<n; i++) printf(" %d",result[i]); printf("\n"); } return 0; }
原文:https://www.cnblogs.com/zhanghaijie/p/10369631.html