char *与const char **函数参数传参问题

传参方法

## 函数

extern void f2 ( const char ** ccc );


const char ch = 'X';
char * ch_ptr;
const char ** ch_pptr = &ch_ptr; // This is not allowed, because...

## 传参

f2(ch_ptr)

## 如果遇到报错

f2(const_cast<const char**>(ch_ptr));

参考

const char * vs. const char ** function argument [duplicate]
https://stackoverflow.com/questions/32096734/const-char-vs-const-char-function-argument
c++: why can‘t we convert char ** to const char ** [duplicate]
https://stackoverflow.com/questions/32779079/c-why-cant-we-convert-char-to-const-char

char *与const char **函数参数传参问题

原文：https://www.cnblogs.com/17bdw/p/10353434.html