每次迭代从3个列表里各取一个数据
相当于把3个里边拼接成了一个列表再迭代
from random import randint
l1 = [‘jwang‘, ‘Tom‘, ‘Jerry‘, ‘Liming‘]
l2 = [randint(60, 100) for x in range(4)]
l3 = [randint(60, 100) for x in range(4)]
l4 = [randint(60, 100) for x in range(4)]
print(l1)
print(l2)
print(l3)
print(l4)
for name, math, english, physics in zip(l1, l2, l3, l4):
print("name:%s, math:%s, english:%s, physics:%s" % (name, math, english, physics))
output:
[‘jwang‘, ‘Tom‘, ‘Jerry‘, ‘Liming‘]
[64, 69, 94, 93]
[81, 89, 64, 80]
[69, 94, 81, 62]
name:jwang, math:64, english:81, physics:69
name:Tom, math:69, english:89, physics:94
name:Jerry, math:94, english:64, physics:81
name:Liming, math:93, english:80, physics:62
from random import randint
l1 = [‘jwang‘, ‘Tom‘, ‘Jerry‘, ‘Liming‘]
l2 = [randint(60, 100) for x in range(4)]
l3 = [randint(60, 100) for x in range(4)]
l4 = [randint(60, 100) for x in range(3)]
print(l1)
print(l2)
print(l3)
print(l4)
for name, math, english, physics in zip(l1, l2, l3, l4):
print("name:%s, math:%s, english:%s, physics:%s" % (name, math, english, physics))
output:
[‘jwang‘, ‘Tom‘, ‘Jerry‘, ‘Liming‘]
[92, 66, 91, 75]
[72, 92, 100, 77]
[71, 67, 98]
name:jwang, math:92, english:72, physics:71
name:Tom, math:66, english:92, physics:67
name:Jerry, math:91, english:100, physics:98
for x in chain([1, 2, 3, 4],[‘a‘, ‘b‘, ‘c‘]):
print(x)
output:
1
2
3
4
a
b
c
from itertools import chain
l1 = [randint(60, 100) for x in range(4)]
l2 = [randint(60, 100) for x in range(4)]
l3 = [randint(60, 100) for x in range(4)]
l4 = [randint(60, 100) for x in range(3)]
print(l1)
print(l2)
print(l3)
print(l4)
count = 0
for x in chain(l1, l2, l3, l4):
if x>90:
count += 1
print(count)
output:
[66, 94, 66, 73]
[98, 90, 90, 60]
[69, 83, 75, 61]
[71, 83, 68]
2
原文:https://www.cnblogs.com/wangjiale1024/p/10350465.html