char * itoa ( int value, char * str, int base );
Converts an integer value to a null-terminated string
using the specified base and stores the result in the array
given by str parameter.
If base is
10 and value is negative, the resulting string is preceded
with a minus sign (-). With any
other base, valueis always considered
unsigned.
str should be an array long enough to contain any
possible value: (sizeof(int)*8+1) for radix=2,
i.e. 17 bytes in 16-bits platforms and 33 in 32-bits platforms.
A pointer to the resulting null-terminated string, same as
parameter str.
This function is not defined in ANSI-C and
is not part of C++, but is supported by some
compilers.
A standard-compliant alternative for some cases may be sprintf:
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/* itoa example */#include <stdio.h>#include <stdlib.h>int main (){ int
i; char
buffer [33]; printf
("Enter a number: "); scanf
("%d",&i); itoa (i,buffer,10); printf
("decimal: %s\n",buffer); itoa (i,buffer,16); printf
("hexadecimal: %s\n",buffer); itoa (i,buffer,2); printf
("binary: %s\n",buffer); return
0;} |
Output:
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Enter a number: 1750decimal: 1750hexadecimal: 6d6binary: 11011010110 |
itoa : Convert integer to string
原文：http://www.cnblogs.com/cindy-hu-23/p/3547959.html