题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4902
1 10 16807 282475249 1622650073 984943658 1144108930 470211272 101027544 1457850878 1458777923 2007237709 10 1 3 6 74243042 2 4 8 16531729 1 3 4 1474833169 2 1 8 1131570933 2 7 9 1505795335 2 3 7 101929267 1 4 10 1624379149 2 2 8 2110010672 2 6 7 156091745 1 2 5 937186357
16807 937186357 937186357 937186357 937186357 1 1 1624379149 1624379149 1624379149
代码如下:
#include <cstdio>
#include <algorithm>
#include <iostream>
using namespace std;
#define LL long long
const int maxn = 111111;
#define ls (rt << 1)
#define rs (rt << 1 | 1)
#define lson l, mid, ls
#define rson mid+1, r, rs
//num数组表示该区间是否都是同一个数,如果是num就等于这个数,否则等-1
int num[maxn << 2];
//flag标记,表示该区间是否应该被纯色化(变成一个数)。
int flag[maxn << 2];
//mmax数组表示该区间的最大值,因为gcd只对该区间比x大的起作用
int mmax[maxn << 2];
int GCD(int a, int b)
{
return a ? GCD(b%a,a) : b;
}
void Pushup(int rt)
{
if(num[ls] == num[rs])
num[rt] = num[ls];
else
num[rt] = -1;
mmax[rt] = max(mmax[ls], mmax[rs]);
}
void Pushdown(int rt)
{
if(flag[rt] != -1)
{
flag[ls] = flag[rs] = flag[rt];
mmax[ls] = mmax[rs] = mmax[rt];
num[ls] = num[rs] = num[rt];
flag[rt] = -1;
}
}
void build(int l, int r, int rt)
{
flag[rt] = -1;
if(l == r)
{
scanf("%d",&num[rt]);
mmax[rt] = num[rt];//初始化
return ;
}
int mid = (l+r) >> 1;
build(lson);
build(rson);
Pushup(rt);
}
void update(int L, int R, int x, int l, int r, int rt)
{
if(L <= l && r <= R)
{
flag[rt] = num[rt] = mmax[rt] = x;
return ;
}
Pushdown(rt);
int mid = (l+r) >> 1;
if(L <= mid)
update(L, R, x, lson);
if(mid < R)
update(L, R, x, rson);
Pushup(rt);
}
void modify(int L, int R, int x, int l, int r, int rt)
{
if(L <= l && r <= R && num[rt] > x)
{
flag[rt] = num[rt] = mmax[rt] = GCD(num[rt], x);
return ;
}
Pushdown(rt);
int mid = (l+r) >> 1;
if(L <= mid && mmax[ls] > x)
modify(L, R, x, lson);
if(mid < R && mmax[rs] > x)
modify(L, R, x, rson);
Pushup(rt);
}
void Cout(int l, int r, int rt)
{
if(l == r)
{
printf("%d ",num[rt]);
return ;
}
Pushdown(rt);
int mid = (l+r) >> 1;
Cout(lson);
Cout(rson);
}
int main()
{
int T;
int R, L;
int n, m;
int op,l, r, x;
int i, j, k;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
build(1,n,1);
scanf("%d",&m);
for(i = 0; i < m; i++)
{
scanf("%d%d%d%d",&op,&l,&r,&x);
if(op == 1)
{
update(l, r, x, 1, n, 1);
}
else if(op == 2)
{
modify(l, r, x, 1, n, 1);
}
}
Cout(1, n, 1);
printf("\n");
}
return 0;
}
hdu 4902 Nice boat(线段树区间修改,输出最终序列),布布扣,bubuko.com
hdu 4902 Nice boat(线段树区间修改,输出最终序列)
原文:http://blog.csdn.net/u012860063/article/details/38337715