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[leetcode]Same Tree

时间:2014-07-31 23:15:00      阅读:321      评论:0      收藏:0      [点我收藏+]

Same Tree

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

算法思路:

思路1:判断两棵树是否一样,可以根据中序遍历+前(后)序遍历序列得到。

实现略。

思路2:dfs判断

1 public class Solution {
2     public boolean isSameTree(TreeNode p, TreeNode q) {
3         if(p == null && q == null) return true;
4         if((q == null && p != null ) || (p == null && q != null ) || p.val != q.val) return false;
5         return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
6     
7     }
8 }

 

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[leetcode]Same Tree

原文:http://www.cnblogs.com/huntfor/p/3881588.html

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