1 public int singleNumber(int[] A) { 2 int s=0; 3 for(int i=0;i<A.length;i++){ 4 s=s^A[i]; 5 } 6 return s; 7 }
leetcode--012 single number I,布布扣,bubuko.com
leetcode--012 single number I
原文：http://www.cnblogs.com/thehappyyouth/p/3880655.html
