题目大意:一张无向图,问最少设置几个关键点使得有点被覆盖(一个关键点可以覆盖所有与它相连的点),关键点不可以相邻
题解:二分图染色,若不冲突则为较少的一种颜色数
卡点:无
C++ Code:
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#define maxn 10010
#define maxm 100010
int head[maxn], cnt;
struct Edge {
int to, nxt;
} e[maxm << 1];
inline void addE(int a, int b) {
e[++cnt] = (Edge) {b, head[a]}; head[a] = cnt;
}
int n, m, ans;
int res[2];
int C[maxn];
void dfs(int u) {
res[C[u]]++;
for (int i = head[u]; i; i = e[i].nxt) {
int v = e[i].to;
if (!~C[v]) {
C[v] = C[u] ^ 1;
dfs(v);
} else if (C[v] != (C[u] ^ 1)) {
puts("Impossible");
exit(0);
}
}
}
int main() {
scanf("%d%d", &n, &m);
for (int i = 0, a, b; i < m; i++) {
scanf("%d%d", &a, &b);
addE(a, b);
addE(b, a);
}
__builtin_memset(C, -1, sizeof C);
for (int i = 1; i <= n; i++) if (!~C[i]) {
res[0] = res[1] = 0;
C[i] = 1;
dfs(i);
ans += std::min(res[0], res[1]);
}
printf("%d\n", ans);
return 0;
}
原文:https://www.cnblogs.com/Memory-of-winter/p/10013981.html