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908. Smallest Range I

时间:2018-10-21 12:44:59      阅读:149      评论:0      收藏:0      [点我收藏+]

Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i].

After this process, we have some array B.

Return the smallest possible difference between the maximum value of B and the minimum value of B.

Example 1:

Input: A = [1], K = 0
Output: 0
Explanation: B = [1]

Example 2:

Input: A = [0,10], K = 2
Output: 6
Explanation: B = [2,8]

Example 3:

Input: A = [1,3,6], K = 3
Output: 0
Explanation: B = [3,3,3] or B = [4,4,4]

Note:

  1. 1 <= A.length <= 10000
  2. 0 <= A[i] <= 10000
  3. 0 <= K <= 10000
class Solution:
    def smallestRangeI(self, A, K):
        """
        :type A: List[int]
        :type K: int
        :rtype: int
        """
        a,b = max(A),min(A)
        if a-b<=2*K:
            return 0
        else:
            return a-b-2*K

908. Smallest Range I

原文:https://www.cnblogs.com/bernieloveslife/p/9799830.html

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