SQL - 获取多机构最近相同节点

-- Create Branches Table
create table Branches
(
    BranchCode varchar(16)
    ,BranchName nvarchar(32)
    ,L0BCode varchar(16)
    ,L1BCode varchar(16)
    ,L2BCode varchar(16)
    ,L3BCode varchar(16)
    ,L4BCode varchar(16)
    ,L5BCode varchar(16)
    ,L6BCode varchar(16)
    ,L7BCode varchar(16)
)
go


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declare @branches varchar(512) = ‘02078,31696,90100‘
        ,@count int
        ,@branchcode varchar(16)

select @count = COUNT(*) from string_split(@branches,‘,‘) 

;with t1
as
(
select b.L0BCode,b.L1BCode,b.L2BCode,b.L3BCode,b.L4BCode,b.L5BCode,b.L6BCode,b.L7BCode
,iif(isnull(b.L0BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L0BCode ))  as L0Rank
,iif(isnull(b.L1BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L1BCode ))  as L1Rank
,iif(isnull(b.L2BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L2BCode ))  as L2Rank
,iif(isnull(b.L3BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L3BCode ))  as L3Rank
,iif(isnull(b.L4BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L4BCode ))  as L4Rank
,iif(isnull(b.L5BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L5BCode ))  as L5Rank
,iif(isnull(b.L6BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L6BCode ))  as L6Rank
,iif(isnull(b.L7BCode,‘‘) = ‘‘,@count,dense_rank()over(order by b.L7BCode ))  as L7Rank
from 
    Branches b
        inner join
            string_split(@branches,‘,‘)  b2
                on
                    b.BranchCode = b2.value
)

,t2
as
(
select 
    top 1 * 
from
(
    select 
        b.L0BCode,b.L1BCode,b.L2BCode,b.L3BCode,b.L4BCode,b.L5BCode,b.L6BCode,b.L7BCode
        ,sum(L0Rank)over(partition by 1) as L0Sum
        ,sum(L1Rank)over(partition by 1) as L1Sum
        ,sum(L2Rank)over(partition by 1) as L2Sum
        ,sum(L3Rank)over(partition by 1) as L3Sum
        ,sum(L4Rank)over(partition by 1) as L4Sum
        ,sum(L5Rank)over(partition by 1) as L5Sum
        ,sum(L6Rank)over(partition by 1) as L6Sum
        ,sum(L7Rank)over(partition by 1) as L7Sum
    from t1 as b
) as b
order by b.L7BCode desc,b.L6BCode desc,b.L5BCode desc,b.L4BCode desc,b.L3BCode desc,b.L2BCode desc,b.L1BCode desc
)

select 
    @branchcode = 
    (
        case 
            when L7Sum = @count then L7BCode
            when L6Sum = @count then L6BCode
            when L5Sum = @count then L5BCode
            when L4Sum = @count then L4BCode
            when L3Sum = @count then L3BCode
            when L2Sum = @count then L2BCode
            when L1Sum = @count then L1BCode
            when L0Sum = @count then L0BCode
        else
            L0BCode
        end
    )
    
from t2


select @branchcode