Time Limit: 6000/6000 MS (Java/Others) Memory Limit: 510000/510000 K (Java/Others)
Total Submission(s): 5248 Accepted Submission(s): 2014
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int maxn = 45;
const int maxm = (1<<20);
int a[maxn];
LL dp[2][maxm];
int main()
{
int t;
scanf("%d", &t);
for(int k = 1; k <= t; k++)
{
int n, m;
scanf("%d%d", &n, &m);
for(int i = 1; i <= n; i++)
{
scanf("%d", &a[i]);
}
memset(dp, 0, sizeof(dp));
dp[0][0] = 1;
int pre = 0, now = 1;
for(int i = 1; i <= n; i++)
{
for(int j = 0; j < maxm; j++)
{
int x = a[i] ^ j;
dp[now][x] = dp[pre][x] + dp[pre][j];
}
swap(now, pre);
}
LL ans = 0;
for(int i = m; i < maxm; i++)
{
ans += dp[pre][i];
}
printf("Case #%d: %lld\n", k, ans);
}
return 0;
}
原文:https://www.cnblogs.com/songorz/p/9710614.html