Python学习笔记4：多线程的示例二（递归锁）

 1 import threading,time
 2 
 3 def fun1():
 4     print("第一个函数")
 5     lock.acquire()
 6     global num
 7     num +=1
 8     lock.release()
 9     return num
10 
11 def fun2():
12     print("第二个函数")
13     lock.acquire()
14     global num2
15     num2 +=1
16     lock.release()
17     return num2
18 
19 def run3():
20     lock.acquire()
21     res1 = fun1()
22     print(‘--- 两个函数之间的打印 ----‘)
23     res2 = fun2()
24     lock.release()
25     print(res1,res2)
26 
27 num,num2 = 0,0
28 lock = threading.RLock()
29 
30 for i in range(10):
31     t = threading.Thread(target=run3)
32     t.start()
33 
34 
35 
36 while threading.active_count() != 1:
37     time.sleep(1)
38     print("当前线程数为：",threading.active_count())
39 else:
40     print(‘所有线程结束，主进程结束!‘)
41     print(num,num2)