Given a text file file.txt, print just the 10th line of the file.
Example:
Assume that file.txt has the following content:
Line 1
Line 2
Line 3
Line 4
Line 5
Line 6
Line 7
Line 8
Line 9
Line 10
Your script should output the tenth line, which is:
Line 10
#从第10行开始显示，然后取第一行 tail -n +10 file.txt | head -n 1
#打印第10行 sed -n 10p file.txt
awk ‘NR==10 {print $0}‘ file.txt
awk ‘NR==10 ‘ file.txt
cnt=0 while read line do let cnt++ if [ $cnt -eq 10 ];then echo $line exit 0 fi done < file.txt
原文：https://www.cnblogs.com/mengchunchen/p/9301063.html