作业1,文件a.txt内容:每一行内容分别为商品名字,价格,个数
apple 10 3
tesla 100000 1
mac 3000 2
lenovo 30000 3
chicken 10 3
通过代码,将其构建成这种数据类型:
[{‘name‘:‘apple‘,‘price‘:10,‘amount‘:3},{‘name‘:‘tesla‘,‘price‘:1000000,‘amount‘:1}......] 并计算出总价钱。
‘‘‘ 实现方法: 循环句柄,控制循环次数,对item进行切割,形成列表, 在进行for循环添加字典 ‘‘‘ with open(‘a.txt‘, ‘r‘, encoding=‘utf-8‘) as f: li = [] for item in f: # item = apple 10 3 dic = {‘name‘: None, ‘price‘: None, ‘amount‘: None} lst = item.split() # lst = [‘apple‘, ‘10‘, ‘3‘] dic[‘name‘] = lst[0] dic[‘price‘] = lst[1] dic[‘amount‘] = lst[2] li.append(dic) print(li)
作业2,文件a1.txt内容:
name:apple price:10 amount:3 year:2012
name:tesla price:100000 amount:1 year:2013
......
通过代码,将其构建成这种数据类型:
[{‘name‘: ‘apple‘, ‘price‘: ‘10‘, ‘amount‘: ‘3‘}, {‘name‘: ‘tesla‘, ‘price‘: ‘100000‘, ‘amount‘: ‘1‘}]
with open(‘e.txt‘, ‘r‘, encoding=‘utf-8‘) as f: lst = [] sum = 0 for item in f: dic = {} lst1 = item.split(‘ ‘) # [‘name:apple‘, ‘price:10‘, ‘amount:3‘, ‘year:2012\n‘] for el in lst1: # item = ‘name:apple‘ lst2 = el.split(‘:‘) # lst2 = [name, apple] if lst2[0] == ‘year‘: continue dic[lst2[0]] = lst2[1].strip() lst.append(dic) sum += int(dic[‘price‘])*int(dic[‘amount‘]) print(lst) print(sum)
作业3,文件a.1txt内容形式:
序号 部门 人数 平均年龄 备注
1 python 30
26 单身狗
2 Linux 26
30 没对象
3 运营部 20
24 女生多
通过代码,将其构建成这种数据类型:
[{‘序号‘:‘1‘,‘部门‘:Python,‘人数‘:30,‘平均年龄‘:26,‘备注‘:‘单身狗‘},
......]
with open(‘d.txt‘, ‘r‘, encoding=‘utf-8‘) as f: lst = f.readlines() lst1 = [] # 最后打印的列表 new = [] # key的列表 for item in lst[0].split(): # 将第一行的名称添加到new列表里面,之后for循环new列表元素组成字典的key if item != ‘ ‘: new.append(item) # print(new) # [‘序号‘, ‘部门‘, ‘人数‘, ‘平均年龄‘, ‘备注‘] # print(lst[1:]) index = 0 # 实现列表长度的循环 for item in lst[1:]: # n = [] dic = {} # 循环定义字典,添加到列表中 for el in item.split(‘ ‘): # el = [‘1‘, ...] if el != ‘‘: # n = [‘1‘, ‘python‘, ‘30‘, ‘26‘, ‘单身狗\n‘] # n.append(el) dic[new[index]] = el.strip() # 匹配索引位置以键值对的形式添加到列表中 index += 1 if index == len(new): index = 0 lst1.append(dic) print(lst1)
原文：https://www.cnblogs.com/chenrun/p/9157278.html