【leetcode】Linked List Cycle (python)

class Solution:
    # @param head, a ListNode
    # @return a boolean
    def hasCycle(self, head):
        if None == head or None == head.next:
            return False
        pfast = head
        pslow = head
        while pfast and pfast.next:
            pfast = pfast.next.next
            pslow = pslow.next
            if pfast == pslow:
                return True
        return False
        

【leetcode】Linked List Cycle (python),布布扣,bubuko.com

【leetcode】Linked List Cycle (python)

原文：http://blog.csdn.net/shiquxinkong/article/details/37818869