We are given two strings, A and B.
A shift on A consists of taking string A and moving the leftmost character to the rightmost position. For example, if A = ‘abcde‘, then it will be ‘bcdea‘ after one shift on A. Return True if and only if A can become B after some number of shifts on A.
Example 1:
Input: A = ‘abcde‘, B = ‘cdeab‘
Output: true
Example 2:
Input: A = ‘abcde‘, B = ‘abced‘
Output: false
Note:
AandBwill have length at most100.
如果把A的一部分子串移到后面,跟B相等,则返回true
C++(3ms):
1 class Solution { 2 public: 3 bool rotateString(string A, string B) { 4 return (A.size() == B.size() && (A+A).find(B) != string::npos) ; 5 } 6 };