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leetcaode Hamming Distance

时间:2018-02-25 16:41:12      阅读:243      评论:0      收藏:0      [点我收藏+]

The Hamming distance between two integers is the number of positions at which the corresponding bits are different.

Given two integers x and y, calculate the Hamming distance.

Note:
0 ≤ xy < 231.

example:

Input: x = 1, y = 4

Output: 2

Explanation:
1   (0 0 0 1)
4   (0 1 0 0)
       ↑   ↑

The above arrows point to positions where the corresponding bits are different.

 

实现代码:

class Solution {
public:
    int hammingDistance(int x, int y) {
        if ((x ^ y) == 0) return 0;
        return (x ^ y) % 2 + hammingDistance(x / 2, y / 2);
    }
};

 

leetcaode Hamming Distance

原文:https://www.cnblogs.com/smallprogrammer/p/8469588.html

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