#!/bin/bash
if [ $# != 1 ]
then
echo "usage: 1.sh # (#>1) "
exit 1
else
for ((i=1;i<=$1;i++))
do
for ((j=$i;j<=$1;j++))
do
echo -n " "
done
for ((k=1;k<=$i;k++))
do
echo -n " "
done
echo
done
i1=$[$1/2] //确定
for ((i=1;i<=$i1;i++))
do
j1=$[($12-1)/2+1-$1/4]
for ((j=1;j<=$j1;j++))
do
echo -n " "
done
k1=$[$1-$j1+1]
for ((k=1;k<=$k1;k++))
do
echo -n "* "
done
echo
done
fi圣诞树中级
原文：http://blog.51cto.com/11972980/2071821
