Description
Input
Output
Sample Input
3 565 9876543210 9876105432
Sample Output
556 1234567890 1678905432
思路:贪心的从后向前开始,大的放后面,然后找到当前最小的,从后面来也可以排除0放到第一个的可能
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 200;
char str[MAXN];
char head[MAXN],tail[MAXN];
int main() {
int t;
scanf("%d", &t);
while (t--) {
scanf("%s", str);
int n = strlen(str);
int a = 0, b = 0;
int cnt = n-1;
while (str[cnt] == '0' && cnt > 0)
cnt--;
for (int i = cnt; i >= 0; i--)
if (str[cnt] > str[i] && str[i] != '0')
cnt = i;
head[a++] = str[cnt];
for (int i = n-1; i > cnt; i--)
tail[b++] = str[i];
while (a+b < n && cnt > 0) {
int tmp = cnt-1;
for (int j = tmp-1; j >= 0; j--)
if (str[j] < str[tmp])
tmp = j;
head[a++] = str[tmp];
for (int j = cnt-1; j > tmp; j--)
tail[b++] = str[j];
cnt = tmp;
}
for (int i = 0; i < a; i++)
printf("%c", head[i]);
for (int j = b-1; j >= 0; j--)
printf("%c", tail[j]);
printf("\n");
}
return 0;
}HDU - 4550 卡片游戏,布布扣,bubuko.com
原文:http://blog.csdn.net/u011345136/article/details/36899929