F - Proud Merchants

InputThere are several test cases in the input. 

Each test case begin with two integers N, M (1 ≤ N ≤ 500, 1 ≤ M ≤ 5000), indicating the items’ number and the initial money. 
Then N lines follow, each line contains three numbers Pi, Qi and Vi (1 ≤ Pi ≤ Qi ≤ 100, 1 ≤ Vi ≤ 1000), their meaning is in the description. 

The input terminates by end of file marker. 

OutputFor each test case, output one integer, indicating maximum value iSea could get. 

Sample Input

2 10
10 15 10
5 10 5
3 10
5 10 5
3 5 6
2 7 3

Sample Output

5
11

#include <iostream>
#include<stdio.h>
#include<algorithm>
#include<string.h>
using namespace std;
struct node
{
    int v1;
    int c;
    int w;
}a[100000];
int dp[10000];
bool cmp(node a,node b)
{
    return a.c-a.v1<b.c-b.v1;
}
int main()
{
     int n,v;
   while(~scanf("%d%d",&n,&v))
   {

memset(dp,0,sizeof dp);
     for(int i=0;i<n;i++)
     {
         scanf("%d%d%d",&a[i].v1,&a[i].c,&a[i].w);

     }
     sort(a,a+n,cmp);
     for(int i=0;i<n;i++)
        for(int j=v;j>=a[i].c;j--)
     {
         dp[j]=max(dp[j],dp[j-a[i].v1]+a[i].w);
     }
     printf("%d\n",dp[v]);
   }
    return 0;
}

排序的地方注意一下。。。因为A 需要的时间 A。V1+B.c     B的时间是B.V1+A.C;

F - Proud Merchants

原文：http://www.cnblogs.com/2014slx/p/7811933.html