Given an unsorted array of integers, find the length of longest continuous increasing subsequence.
Example 1:
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it‘s not a continuous one where 5 and 7 are separated by 4.
Example 2:
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
class Solution(object):
    def findLengthOfLCIS(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        temp = 1
        result = 1
        if len(nums)==0:
            return 0
        for i in range(1,len(nums),1):
            if nums[i]>nums[i-1]:
                temp +=1
            else:
                temp = 1
            result = max(result,temp)
        return result
674. Longest Continuous Increasing Subsequence
原文:http://www.cnblogs.com/bernieloveslife/p/7692663.html