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628. Maximum Product of Three Numbers

时间:2017-10-15 13:01:26      阅读:259      评论:0      收藏:0      [点我收藏+]

Given an integer array, find three numbers whose product is maximum and output the maximum product.

Example 1:

Input: [1,2,3]
Output: 6

 

Example 2:

Input: [1,2,3,4]
Output: 24

 

Note:

  1. The length of the given array will be in range [3,104] and all elements are in the range [-1000, 1000].
  2. Multiplication of any three numbers in the input won‘t exceed the range of 32-bit signed integer.

求三个乘积最大,注意下负数的情况,两负*一正的情况也需要考虑。

 

1     public int maximumProduct(int[] nums) {
2          if (nums.length<3)
3             return Integer.MIN_VALUE;
4         Arrays.sort(nums);
5         int maxSum = nums[nums.length-1] * nums[nums.length-2] * nums[nums.length-3];
6         int minSum = nums[nums.length-1] * nums[0] * nums[1];
7         return Math.max(maxSum,minSum);
8     }

 

628. Maximum Product of Three Numbers

原文:http://www.cnblogs.com/wzj4858/p/7670262.html

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