Note:
k different could be [1, k+1] are in wiggle sort order. Then there are k different numbers. But in this case, the last difference definitely will be 1. So folllowing difference will duplicate with previous.
class Solution { public int[] constructArray(int n, int k) { int[] result = new int[n]; int maxValue = k + 1; for (int i = 0; i < k + 1; i++) { if (i % 2 == 0) { result[i] = i / 2 + 1; } else { result[i] = maxValue - i / 2; } } for (int i = k + 1; i < n; i++) { result[i] = i + 1; } return result; } }
LeetCode 667: Beautiful Arrangement II
原文：http://www.cnblogs.com/shuashuashua/p/7500911.html