首页 > 其他 > 详细

多级菜单的实现

时间:2017-09-07 15:29:19      阅读:226      评论:0      收藏:0      [点我收藏+]

 

 

利用字典实现多级菜单:

 

area = {
    ‘广西‘:{
        ‘梧州‘:{
            ‘岑溪‘:[‘豆腐酿‘,‘新圩米粉‘,‘茄子酿‘,‘白切鸡‘],
            ‘容县‘:[‘1‘,‘2‘,‘3‘],
            ‘苍梧‘:[‘4‘,‘5‘,‘6‘]
            },
        ‘南宁‘:{
            ‘武鸣区‘:[‘大明山‘,‘伊岭岩‘,‘灵水‘,‘明秀园‘],
            ‘宾阳县‘:[‘鱼生‘,‘宾阳酸辣粉‘]
            }
        },
    ‘广东‘:{
        ‘广州市‘:[‘越秀区‘,‘荔湾区‘,‘‘],
        ‘深圳市‘:[‘福田区‘,‘罗湖区‘,‘宝安区‘],
        ‘珠海市‘:[‘香洲区‘,‘斗门区‘,‘金湾区‘]
        },
    ‘湖南‘:{
        ‘长沙市‘:[‘长沙县‘,‘宁乡县‘,‘雨花区‘],
        ‘湘潭市‘:[‘雨湖区‘,‘湘潭县‘,‘韶山市‘],
        ‘娄底市‘:[‘娄星区‘,‘新化县‘,‘双峰县‘]
          }
}

while True:
    for i in area:
        print(i)

    choice = input(‘\n请输入地方名:‘)
    if choice in area:
        while True:
            for i2 in area[choice]:
                print(‘\t‘,i2)
            choice2 = input(‘\n请输入地方名:‘)
            if choice2 in area[choice]:
                while True:
                    for i3 in area[choice][choice2]:
                        print(‘\t\t‘,i3)
                    choice3 = input(‘\n请输入地方名:‘)
                    if choice3 in area[choice][choice2]:
                            for i4 in area[choice][choice2][choice3]:
                                print(‘\t\t\t‘,i4)
                            choice4 = input(‘\n没有啦,按回车返回上一级:‘)
                            if choice4 == ‘b‘:
                                pass
                            elif choice4 == ‘q‘:
                                exit()
                    if choice3 == ‘b‘:
                        break
                    elif choice3 == ‘q‘:
                        exit()
            if choice2 == ‘b‘:
                break
            elif choice2 == ‘q‘:
                exit()
    if choice == ‘q‘:
        exit()

  

 

多级菜单的实现

原文:http://www.cnblogs.com/relax1949/p/7489908.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!