| Time Limit: 1000MS | Memory Limit: 65536K | |||
| Total Submissions: 7646 | Accepted: 2710 | Special Judge | ||
Description
Input
Output
Sample Input
5 1 10 2 4 3 6 5 8 4 7
Sample Output
4 1 2 3 2 4
Hint
Time 1 2 3 4 5 6 7 8 9 10Other outputs using the same number of stalls are possible.
Stall 1 c1>>>>>>>>>>>>>>>>>>>>>>>>>>>
Stall 2 .. c2>>>>>> c4>>>>>>>>> .. ..
Stall 3 .. .. c3>>>>>>>>> .. .. .. ..
Stall 4 .. .. .. c5>>>>>>>>> .. .. ..
#include<iostream>
#include<cstdio>
#include<queue>
#include<algorithm>
using namespace std;
struct node
{
int l,r,n;
bool operator <(const node &b)const
{
return r>b.r||(r==b.r&&l>b.l);
}
}a[50005];
priority_queue <node> q;
int u[50005];
bool cmp(node a,node b)
{
return a.l<b.l||(a.l==b.l&&a.r<b.r);
}
int main()
{
int n,m;
while(~scanf("%d",&n))
{
int ans=1;
for(int i=1;i<=n;i++)
{
scanf("%d%d",&a[i].l,&a[i].r);
a[i].n=i;
}
sort(a+1,a+n+1,cmp);
q.push(a[1]);
u[a[1].n]=1;
for(int i=2;i<=n;i++)
{
if(!q.empty()&&q.top().r<a[i].l){
u[a[i].n]=u[q.top().n];
q.pop();
}
else{
ans++;
u[a[i].n]=ans;
}
q.push(a[i]);
}
printf("%d\n",ans);
for(int i =1;i<=n;i++){
printf("%d\n",u[i]);
}
while(!q.empty()) // 尤其重要,排空队列
q.pop();
}
}
POJ 3190 Stall Reservations (优先队列)C++
原文:http://www.cnblogs.com/ygtzds/p/7425474.html