mvc ---- ajax 提交过来的Json格式如何处理（解析）

{"fids":"2323","contents":"<p>lsdfjlsdjflsdf</p>"}

 public ActionResult Update(string param2)
 {
      JObject job = (JObject)JsonConvert.DeserializeObject(param2);
      CustomerFollowEntity follow = new CustomerFollowEntity();
      follow.F_Id = job["fids"].ToString();
      follow.F_Description = job["contents"].ToString();
      int s = custapp.Update(follow);
      return Content(s.ToString());
 }

using Newtonsoft;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;