Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 19208 Accepted Submission(s):
6563
#include<iostream>
#include<cstring>
#include<cstdio>
#include<queue>
#include<stack>
#include<vector>
#include<algorithm>
//#include<cmath>
using namespace std;
const int INF = 9999999;
#define LL long long
inline int read(){
int x=0,f=1;char c=getchar();
for(;!isdigit(c);c=getchar()) if(c==‘-‘) f=-1;
for(;isdigit(c);c=getchar()) x=x*10+c-‘0‘;
return x*f;
}
int N,M;
int a[100001];
int heap[100001];
int len;
void insert(int x){
heap[++len]=x;
for(int k=len;k!=1;k/=2){
if(heap[k]<heap[k/2]) swap(heap[k],heap[k/2]);
else break;
}
return ;
}
void delet(){
if(len==0) return ;
heap[1]=heap[len];len--;
for(int k=1;k*2<=len;){
if((k*2<=len)&&(k*2+1>len)){
if(heap[k*2]<heap[k]) swap(heap[k*2],heap[k]),k*=2;
else break;
}
else{
if(heap[k*2]<heap[k]||heap[k*2+1]<heap[k]){
if(heap[k*2]<heap[k*2+1]) swap(heap[k],heap[k*2]),k*=2;
else swap(heap[k],heap[k*2+1]),k*=2,k++;
}
else break;
}
}
return ;
}
int ans[100001];
int main(){
//freopen(".in","r",stdin);
//freopen(".out","w",stdout);
while(scanf("%d%d",&N,&M)!=EOF){
len=0;
for(int i=1;i<=N;i++) a[i]=read();
for(int i=1;i<=N;i++)
for(int j=i+1;j<=N;j++){
insert(a[i]+a[j]);
if(len>M) delet();
}
for(int i=1;i<=M;i++) ans[i]=heap[1],delet();
for(int i=M;i>1;i--) printf("%d ",ans[i]);
printf("%d\n",ans[1]);
}
return 0;
}
优先队列代码:
#include<iostream>
#include<cstring>
#include<cstdio>
#include<queue>
#include<stack>
#include<vector>
#include<algorithm>
//#include<cmath>
using namespace std;
const int INF = 9999999;
#define LL long long
inline int read(){
int x=0,f=1;char c=getchar();
for(;!isdigit(c);c=getchar()) if(c==‘-‘) f=-1;
for(;isdigit(c);c=getchar()) x=x*10+c-‘0‘;
return x*f;
}
int N,M;
priority_queue<int ,vector<int> , greater<int> > Que;
int a[100001];
int ans[100001];
int main(){
//freopen(".in","r",stdin);
//freopen(".out","w",stdout);
while(scanf("%d%d",&N,&M)!=EOF){
for(int i=1;i<=N;i++) a[i]=read();
for(int i=1;i<=N;i++)
for(int j=i+1;j<=N;j++){
Que.push(a[i]+a[j]);
if(Que.size()>M) Que.pop();
}
for(int i=1;i<=M;i++) ans[i]=Que.top(),Que.pop();
for(int i=M;i>1;i--) printf("%d ",ans[i]);
printf("%d\n",ans[1]);
}
return 0;
}
原文:http://www.cnblogs.com/wxjor/p/7223054.html