5 6 .XX.1. ..X.2. 2...X. ...XX. XXXXX. 5 6 .XX.1. ..X.2. 2...X. ...XX. XXXXX1 5 6 .XX... ..XX1. 2...X. ...XX. XXXXX.
It takes 13 seconds to reach the target position, let me show you the way. 1s:(0,0)->(1,0) 2s:(1,0)->(1,1) 3s:(1,1)->(2,1) 4s:(2,1)->(2,2) 5s:(2,2)->(2,3) 6s:(2,3)->(1,3) 7s:(1,3)->(1,4) 8s:FIGHT AT (1,4) 9s:FIGHT AT (1,4) 10s:(1,4)->(1,5) 11s:(1,5)->(2,5) 12s:(2,5)->(3,5) 13s:(3,5)->(4,5) FINISH It takes 14 seconds to reach the target position, let me show you the way. 1s:(0,0)->(1,0) 2s:(1,0)->(1,1) 3s:(1,1)->(2,1) 4s:(2,1)->(2,2) 5s:(2,2)->(2,3) 6s:(2,3)->(1,3) 7s:(1,3)->(1,4) 8s:FIGHT AT (1,4) 9s:FIGHT AT (1,4) 10s:(1,4)->(1,5) 11s:(1,5)->(2,5) 12s:(2,5)->(3,5) 13s:(3,5)->(4,5) 14s:FIGHT AT (4,5) FINISH God please help our poor hero. FINISH
1.abduct:绑架,诱拐。使外展
2.假设结构体中有构造函数,用该结构体类型去定义变量时,必须用构造函数去初始化变量,否则编译通只是
3.代码:
#include<cstdio>
#include<cstring>
#include<queue>
#include<stack>
using namespace std;
struct node
{
int x,y,t;
node(int a,int b,int c):x(a),y(b),t(c) {}//构造函数
void Set(int a,int b,int c)//设置函数
{
x=a;
y=b;
t=c;
}
bool operator <(const node &a)const//让优先队列的优先级:t小的,优先级高
{
return a.t<t;
}
};
struct node1
{
int x,y;
};
int n,m;
char mat[105][105];
bool vis[105][105];
node1 matt[105][105];//记录父亲坐标
int dir[4][2]= {1,0,0,1,-1,0,0,-1};
bool flag;
void bfs()
{
memset(vis,0,sizeof(vis));
priority_queue<node> Q;
node first=node(0,0,0);
Q.push(first);
vis[first.x][first.y]=1;
matt[0][0].x=0;
matt[0][0].y=0;
while(!Q.empty())
{
first=Q.top();
Q.pop();
if(first.x==n-1&&first.y==m-1)
{
flag=1;
printf("It takes %d seconds to reach the target position, let me show you the way.\n",first.t);
stack<node1> S;//把路径存储在栈里
node1 e;
e.x=n-1;
e.y=m-1;
S.push(e);
while(1)
{
e=S.top();
if(e.x==matt[e.x][e.y].x&&e.y==matt[e.x][e.y].y)
{
break;
}
node1 ee;
ee.x=matt[e.x][e.y].x;
ee.y=matt[e.x][e.y].y;
S.push(ee);
}
for(int i=1; i<=first.t; i++)//输出路径
{
printf("%ds:",i);
if(mat[S.top().x][S.top().y]!=‘.‘)
{
printf("FIGHT AT (%d,%d)\n",S.top().x,S.top().y);
mat[S.top().x][S.top().y]--;
if(mat[S.top().x][S.top().y]==‘0‘)
{
mat[S.top().x][S.top().y]=‘.‘;
}
}
else
{
printf("(%d,%d)",S.top().x,S.top().y);
S.pop();
printf("->(%d,%d)\n",S.top().x,S.top().y);
}
}
printf("FINISH\n");
break;
}
node next=node(0,0,0);
for(int i=0; i<4; i++)
{
int tx=first.x+dir[i][0];
int ty=first.y+dir[i][1];
if(tx>=n||tx<0||ty>=m||ty<0||vis[tx][ty]==1)
{
continue;
}
else if(mat[tx][ty]==‘X‘)
{
continue;
}
else if(mat[tx][ty]==‘.‘)
{
next.Set(tx,ty,first.t+1);
matt[tx][ty].x=first.x;
matt[tx][ty].y=first.y;
vis[tx][ty]=1;
Q.push(next);
}
else
{
next.Set(tx,ty,first.t+1+mat[tx][ty]-‘0‘);
vis[tx][ty]=1;
matt[tx][ty].x=first.x;
matt[tx][ty].y=first.y;
Q.push(next);
}
}
}
if(!flag)
printf("God please help our poor hero.\nFINISH\n");
}
int main()
{
while(scanf("%d%d",&n,&m)==2)
{
for(int i=0; i<n; i++)
{
scanf("%s",mat[i]);
}
flag=0;
bfs();
}
return 0;
}
HDU 1026 Ignatius and the Princess I(BFS+记录路径)
原文:http://www.cnblogs.com/cynchanpin/p/7000820.html