题目来源:Light OJ 1291 Real Life Traffic
题意:最少添加几条边 可以使全图边双连通
思路:缩点 重新构图 答案就是(叶子节点数+1)/ 2
#include <vector>
#include <cstdio>
#include <cstring>
#include <stack>
#include <algorithm>
using namespace std;
const int maxn = 10010;
struct Edge
{
int u, v;
Edge(){}
Edge(int u, int v): u(u), v(v){}
};
vector <int> a[maxn];
int pre[maxn];
int low[maxn];
int bccno[maxn];
int dfs_clock;
int bcc_cnt;
int bri;
int n, m;
int degree[maxn];
stack <int> S;
void dfs(int u, int fa)
{
low[u] = pre[u] = ++dfs_clock;
S.push(u);
for(int i = 0; i < a[u].size(); i++)
{
int v = a[u][i];
if(v == fa)
continue;
if(!pre[v])
{
dfs(v, u);
low[u] = min(low[u], low[v]);
}
else if(v != fa)
low[u] = min(low[u], pre[v]);
}
if(low[u] == pre[u])
{
bcc_cnt++;
while(1)
{
int x = S.top(); S.pop();
bccno[x] = bcc_cnt;
if(x == u)
break;
}
}
}
void find_bcc()
{
memset(pre, 0, sizeof(pre));
memset(bccno, 0, sizeof(bccno));
dfs_clock = bcc_cnt = bri = 0;
for(int i = 0; i < n; i++)
if(!pre[i])
dfs(i, -1);
}
int main()
{
int cas = 1;
int T;
scanf("%d", &T);
while(T--)
{
scanf("%d %d", &n, &m);
for(int i = 0; i <= n; i++)
a[i].clear();
while(m--)
{
int u, v;
scanf("%d %d", &u, &v);
a[u].push_back(v);
a[v].push_back(u);
}
find_bcc();
memset(degree, 0, sizeof(degree));
for(int u = 0; u < n; u++)
{
for(int i = 0; i < a[u].size(); i++)
{
int v = a[u][i];
if(bccno[u] != bccno[v])
{
degree[bccno[u]]++;
degree[bccno[v]]++;
}
}
}
int ans = 0;
for(int i = 1; i <= bcc_cnt; i++)
if(degree[i] == 2)
ans++;
printf("Case %d: %d\n", cas++, (ans+1)/2);
}
return 0;
}Light OJ 1291 Real Life Traffic 双连通最少添边数,布布扣,bubuko.com
Light OJ 1291 Real Life Traffic 双连通最少添边数
原文:http://blog.csdn.net/u011686226/article/details/29188895