1 >>> a = [1, 2, 3, 4, 5, 6] 2 >>> zip(*([iter(a)] * 2)) 3 [(1, 2), (3, 4), (5, 6)]
函数形式：
1 >>> group_adjacent = lambda a, k: zip(*([iter(a)] * k)) 2 >>> group_adjacent(a, 3) 3 [(1, 2, 3), (4, 5, 6)] 4 >>> group_adjacent(a, 2) 5 [(1, 2), (3, 4), (5, 6)] 6 >>> group_adjacent(a, 1) 7 [(1,), (2,), (3,), (4,), (5,), (6,)]
切片形式：
1 >>> zip(a[::2], a[1::2]) 2 [(1, 2), (3, 4), (5, 6)] 3 4 >>> zip(a[::3], a[1::3], a[2::3]) 5 [(1, 2, 3), (4, 5, 6)]
列表推导式：
1 >>> group_adjacent = lambda a, k: zip(*(a[i::k] for i in range(k))) 2 >>> group_adjacent(a, 3) 3 [(1, 2, 3), (4, 5, 6)] 4 >>> group_adjacent(a, 2) 5 [(1, 2), (3, 4), (5, 6)] 6 >>> group_adjacent(a, 1) 7 [(1,), (2,), (3,), (4,), (5,), (6,)]
原文：http://www.cnblogs.com/WhatTTEver/p/6942625.html