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grep -rl 'python' /root

时间:2017-06-04 00:07:54      阅读:422      评论:0      收藏:0      [点我收藏+]
# grep -rl ‘python‘ /root  搜索root目录下文件内容包含python的文件名路径
import os

def init(func):
    def wrapper(*args,**kwargs):
        res = func(*args,**kwargs)
        next(res)
        return res
    return wrapper

@init
def search(target):
    while True:
        search_path = yield
        g=os.walk(search_path)
        for par_dir,_,files in g:
            for file in files:
                file_abs_path = r‘%s\%s‘ % (par_dir,file)
                target.send(file_abs_path)


@init
def opener(target):
    while True:
        file_abs_path = yield
        with open(file_abs_path,‘r‘,encoding=‘utf-8‘) as f:
            target.send((file_abs_path,f))


@init
def cat(target):
    while True:
        file_abs_path,f = yield
        for line in f:
            tag =target.send((file_abs_path,line))   #注意:对于需要传两个yield的,在send时需要将这两个值放在一个元组中传递(())
            if tag:
                break

@init
def grep(target,pattern):
    tag = False
    while True:
        file_abs_path,line = yield tag
        tag = False
        if pattern in line:
            tag = True
            target.send(file_abs_path)

@init
def printer():
    while True:
        file_abs_path = yield
        print(file_abs_path)

#调用
x = r‘D:\Python_OldBoy\课程\day5\day5\a‘
g = search(opener(cat(grep(printer(),‘python‘))))
g=  search(opener(cat(grep(printer(),‘python‘))))
g.send(x)

  

grep -rl 'python' /root

原文:http://www.cnblogs.com/wangkc/p/6938913.html

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