/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
ListNode *head = new ListNode(0);
ListNode *p = head,*q=NULL;
int num = 0;
int flag = 0;
while (l1!= NULL||l2!= NULL)
{
if (l1 != NULL && l2 != NULL)
{
int sum = l1->val + l2->val + flag;
flag=sum/10;
int Lsum = sum % 10;
p->val = Lsum;
q = p;
p->next = new ListNode(0);
p = p->next;
l1 = l1->next;
l2 = l2->next;
}
else if (l1 == NULL&&l2 != NULL)
{
int sum = l2->val + flag;
flag=sum/10;
int Lsum = sum % 10;
p->val = Lsum;
q = p;
p->next = new ListNode(0);
p = p->next;
l2=l2->next;
}
else
{
int sum = l1->val + flag;
flag=sum/10;
int Lsum = sum % 10;
p->val = Lsum;
q = p;
p->next = new ListNode(0);
p = p->next;
l1=l1->next;
}
}
if (l1 == NULL&&l2 == NULL)
{
if (flag == 0)
{
delete p;
q->next = NULL;
}
else
p->val = flag;
return head;
}
}
};本文出自 “算法设计” 博客,请务必保留此出处http://shineprince.blog.51cto.com/10293320/1913899
原文:http://shineprince.blog.51cto.com/10293320/1913899