首页 > 其他 > 详细

23. Merge k Sorted Lists

时间:2017-03-31 18:57:17      阅读:150      评论:0      收藏:0      [点我收藏+]

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* mergeTwoLists(ListNode* l1,ListNode* l2){
        if(!l1)return l2;
        if(!l2)return l1;
        ListNode *p=l1,*q=l2,*head=NULL,*tail=NULL;
        while(p&&q){
            if(p->val<q->val){
                if(!head){head=p;}
                else tail->next=p;
                tail=p;
                p=p->next;
            }
            else {
                if(!head){head=q;}
                else tail->next=q;
                tail=q;
                q=q->next;
            }
        }
        if(p)tail->next=p;
        else tail->next=q;
        return head;
    }
    ListNode* mergeKLists(vector<ListNode*>& lists) {
        if(lists.size()==0)return NULL;
        if(lists.size()==1)return lists[0];
        if(lists.size()==2)return mergeTwoLists(lists[0],lists[1]);
        vector<ListNode*>subList(lists.begin(),lists.begin()+lists.size()/2);
        vector<ListNode*>rest(lists.begin()+lists.size()/2,lists.begin()+lists.size());
        return mergeTwoLists(mergeKLists(subList),mergeKLists(rest));
    }
};

 

23. Merge k Sorted Lists

原文:http://www.cnblogs.com/tsunami-lj/p/6652742.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!