You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
You may assume the two numbers do not contain any leading zero, except the number 0 itself.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
python代码段
# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def addTwoNumbers(self, l1, l2): """ :type l1: ListNode :type l2: ListNode :rtype: ListNode """ tag = 0 if l1.val+l2.val>9: l3 = ListNode((l1.val+l2.val)%10) tag = 1 else: l3 = ListNode(l1.val+l2.val) tag = 0 l3_copy = l3 l1next = ListNode(0) if l1.next==None else l1.next l2next = ListNode(0) if l2.next==None else l2.next if l1.next==None and l2.next==None and tag ==1: l3_copy.next = ListNode(1) if not(l1.next==None and l2.next==None): while 1: if tag == 1: if l1next.val+l2next.val+1>9: l3_copy.next = ListNode((l1next.val+l2next.val+1)%10) tag = 1 else: l3_copy.next = ListNode(l1next.val+l2next.val+1) tag = 0 else: if l1next.val+l2next.val>9: l3_copy.next = ListNode((l1next.val+l2next.val)%10) tag = 1 else: l3_copy.next = ListNode(l1next.val+l2next.val) tag = 0 l3_copy = l3_copy.next if l1next.next==None and l2next.next==None: if tag == 1: l3_copy.next = ListNode(1) break; l1next = ListNode(0) if l1next.next==None else l1next.next l2next = ListNode(0) if l2next.next==None else l2next.next return l3
这里需要说明一下leetcode给出的ListNode类型的操作方式：
idx = ListNode(3) n = idx n.next = ListNode(4) n = n.next n.next = ListNode(5) n = n.next return idx # idx[3,4,5]
原文：http://www.cnblogs.com/kuqs/p/6531556.html