def f(n, arg1=0, arg2=1, arg3=1):
while n >0:
arg3 = arg1 + arg2
i = arg3 - arg2
print(i)
arg1, arg2 = arg2, arg1 + arg2
n -= 1
return f(n, arg1, arg2)
f(1)
原文：http://www.cnblogs.com/jack410/p/6484698.html