先声明一个空列表：
>>> names = [] >>> names []
可以存多个值：
>>> names = ["wangwang","maomao"] >>> names [‘wangwang‘, ‘maomao‘]
如何取值：
>>> names[1] ‘maomao‘
如何修改：
>>> names[0] = "gougou" >>> names [‘gougou‘, ‘maomao‘]
增加：
>>> names.append("miaomiao")
>>> names
[‘gougou‘, ‘maomao‘, ‘miaomiao‘]
插入：
>>> names [‘gougou‘, ‘maomao‘, ‘miaomiao‘] >>> names.insert(2,"new") >>> names [‘gougou‘, ‘maomao‘, ‘new‘, ‘miaomiao‘]
删除：
第一种方法：
>>> names [‘gougou‘, ‘maomao‘, ‘new‘, ‘miaomiao‘] >>> del names[0] #根据索引删除 >>> names [‘maomao‘, ‘new‘, ‘miaomiao‘]
第二种方法：
>>> names
[‘maomao‘, ‘new‘, ‘miaomiao‘]
>>> names.remove("new") #根据名字删除
>>> names
[‘maomao‘, ‘miaomiao‘]
查找：
>>> names
[‘maomao‘, ‘miaomiao‘, ‘wangwang‘, ‘liyang‘, ‘zhangsi‘, ‘jack‘, ‘mack‘, ‘rain‘,
‘yangle‘, ‘wangjie‘, ‘lirun‘, ‘xiaojie‘]
>>> names.index("liyang") #查找索引
3
>>> names[3]
‘liyang‘
>>> names [names.index("liyang")] = "LiYang" #根据索引重新赋值
>>> names
[‘maomao‘, ‘miaomiao‘, ‘wangwang‘, ‘LiYang‘, ‘zhangsi‘, ‘jack‘, ‘mack‘, ‘rain‘,
‘yangle‘, ‘wangjie‘, ‘lirun‘, ‘xiaojie‘]
统计某个姓名是否有重名：
>>> names.count("maomao")
2
排序：
>>> names [‘maomao‘, ‘miaomiao‘, ‘wangwang‘, ‘LiYang‘, ‘zhangsi‘, ‘jack‘, ‘mack‘, ‘rain‘, ‘yangle‘, ‘wangjie‘, ‘lirun‘, ‘xiaojie‘, ‘maomao‘] >>> names.sort() #根据ASCII排序 >>> names [‘LiYang‘, ‘jack‘, ‘lirun‘, ‘mack‘, ‘maomao‘, ‘maomao‘, ‘miaomiao‘, ‘rain‘, ‘wan gjie‘, ‘wangwang‘, ‘xiaojie‘, ‘yangle‘, ‘zhangsi‘]
从大到小排序：
>>> names.reverse() >>> names [‘zhangsi‘, ‘yangle‘, ‘xiaojie‘, ‘wangwang‘, ‘wangjie‘, ‘rain‘, ‘miaomiao‘, ‘mao mao‘, ‘maomao‘, ‘mack‘, ‘lirun‘, ‘jack‘, ‘LiYang‘]
取值：
>>> names [‘zhangsi‘, ‘yangle‘, ‘xiaojie‘, ‘wangwang‘, ‘wangjie‘, ‘rain‘, ‘miaomiao‘, ‘mao mao‘, ‘maomao‘, ‘mack‘, ‘lirun‘, ‘jack‘, ‘LiYang‘] >>> names[3:5] #取第3和第4。注意：切片顾头不顾尾 [‘wangwang‘, ‘wangjie‘] >>> names[-1]。 #取最后一个 ‘LiYang‘ >>> names[-3:-1] #倒数第三位和倒数第二位，注意永远是从左到右切片的 [‘lirun‘, ‘jack‘]
打印所有的基数位：
>>> names
[‘zhangsi‘, ‘yangle‘, ‘xiaojie‘, ‘wangwang‘, ‘wangjie‘, ‘rain‘, ‘miaomiao‘, ‘mao
mao‘, ‘maomao‘, ‘mack‘, ‘lirun‘, ‘jack‘, ‘LiYang‘]
>>> names[0::2] #从头到尾，2为步长
[‘zhangsi‘, ‘xiaojie‘, ‘wangjie‘, ‘miaomiao‘, ‘maomao‘, ‘lirun‘, ‘LiYang‘]
>>> len(name_list)
2
>>> len(name_list)
2
>>> "wuxin" in name_list
True
[
"daoxin",("seven","wuxin")
]
原文：http://www.cnblogs.com/fkkk/p/6401775.html