fromkeys()
>>> dict1={}
>>> dict1.fromkeys((1,2,3))#会自动为没有赋值的值建立none
{1: None, 2: None, 3: None}
>>> dict1.fromkeys((1,2,3),‘number‘)＃将前一个括号分别与后面结合成项
{1: ‘number‘, 2: ‘number‘, 3: ‘number‘}
>>> dict1.fromkeys((1,2,3),(‘one‘,‘two‘,‘three‘))＃将前面括号分别后后面括号整体结合组成项
{1: (‘one‘, ‘two‘, ‘three‘), 2: (‘one‘, ‘two‘, ‘three‘), 3: (‘one‘, ‘two‘, ‘three‘)}
>>> dict1.fromkeys((1,3),‘good‘)＃试图修改上一步中，1和3的值，但是结果是新建一个字典，内涵1和3，如果名称相同则会覆盖之前的
{1: ‘good‘, 3: ‘good‘}
>>> dict1.fromkeys((1,2,3),(‘one‘,‘two‘,‘three‘))
>>> dict1.fromkeys((1,3),‘数字‘)＃名称相同则会覆盖之前的
fromkeys()＃列举32个赞
>>> dict1 = dict1.fromkeys(range(32),‘赞‘)
keys()＃打印键
>>> for eachkey in dict1.keys():
print(eachkey)
values()＃打印值
>>> for eachvalue in dict1.value():
print(eachvalue)
items()# 打印项
>>> for eachValue in dict1.values():
print(eachValue)
get（）函数
>>> dict1.get(31)
‘赞‘
>>> dict1.get(32)
>>> print(dict1.get(32))
None
>>> dict1.get(32,‘木有‘)＃前面找不到时就打印后面的内容
‘木有‘
>>>
fromkeys() keys() values() items()
原文：http://www.cnblogs.com/themost/p/6371993.html