0001特殊的for迭代zip函数

>>> a = [1,2,3,4,5]

>>> b = [9,8,7,6,5]

>>> length = len(a) if len(a)<len(b) else len(b)

>>> length

5

>>> c = zip(a,b)

>>> c

[(1, 9), (2, 8), (3, 7), (4, 6), (5, 5)]

>>>zip(*c)

[(1,2,3,4,5), (9,8,7,6,5)]

>>> d = []

>>> for x,y in zip(a,b):

　　      d.append(x+y)

>>> d

[10, 10, 10, 10, 10]

0001特殊的for迭代zip函数

原文：http://www.cnblogs.com/zftylj/p/python0001.html