Given a string, find the first non-repeating character in it and return it‘s index. If it doesn‘t exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
class Solution(object): def firstUniqChar(self, s): """ :type s: str :rtype: int """ l=[0]*26 for i in s: l[ord(i)-97]+=1 for index,i in enumerate(s): if l[ord(i)-97]==1: return index return -1
387. First Unique Character in a String
原文：http://www.cnblogs.com/rocksolid/p/6289194.html