Once upon a time there was a greedy King who ordered his chief Architect to build a wall around the King‘s castle. The King was so greedy, that he would not listen to his Architect‘s proposals to build a beautiful brick wall with a perfect shape and nice tall towers. Instead, he ordered to build the wall around the whole castle using the least amount of stone and labor, but demanded that the wall should not come closer to the castle than a certain distance. If the King finds that the Architect has used more resources to build the wall than it was absolutely necessary to satisfy those requirements, then the Architect will loose his head. Moreover, he demanded Architect to introduce at once a plan of the wall listing the exact amount of resources that are needed to build the wall. 
 
Your task is to help poor Architect to save his head, by writing a 
program that will find the minimum possible length of the wall that he 
could build around the castle to satisfy King‘s requirements.
The task is somewhat simplified by the fact, that the King‘s castle 
has a polygonal shape and is situated on a flat ground. The Architect 
has already established a Cartesian coordinate system and has precisely 
measured the coordinates of all castle‘s vertices in feet.
The
 first line of the input file contains two integer numbers N and L 
separated by a space. N (3 <= N <= 1000) is the number of vertices
 in the King‘s castle, and L (1 <= L <= 1000) is the minimal 
number of feet that King allows for the wall to come close to the 
castle.
Next N lines describe coordinates of castle‘s vertices in a 
clockwise order. Each line contains two integer numbers Xi and Yi 
separated by a space (-10000 <= Xi, Yi <= 10000) that represent 
the coordinates of ith vertex. All vertices are different and the sides 
of the castle do not intersect anywhere except for vertices.
Write
 to the output file the single number that represents the minimal 
possible length of the wall in feet that could be built around the 
castle to satisfy King‘s requirements. You must present the integer 
number of feet to the King, because the floating numbers are not 
invented yet. However, you must round the result in such a way, that it 
is accurate to 8 inches (1 foot is equal to 12 inches), since the King 
will not tolerate larger error in the estimates.
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <iostream>
#include <algorithm>
#define MAXN 3010
#define Eps 1e-18
#define Pi 3.1415926535
using namespace std;
struct Vctor{
  double x, y;
  Vctor() {}
  Vctor(double _x, double _y) : x(_x), y(_y) {}
  bool operator == (const Vctor b)const {return x == b.x && y == b.y;}
  bool operator < (const Vctor b)const {return x < b.x || (x == b.x && y < b.y);}
} d[MAXN], _pb[MAXN], e[MAXN];
Vctor operator + (Vctor a, Vctor b) {return Vctor(a.x + b.x, a.y + b.y);}
Vctor operator - (Vctor a, Vctor b) {return Vctor(a.x - b.x, a.y - b.y);}
Vctor operator * (Vctor a, double b) {return Vctor(a.x * b, a.y * b);}
Vctor operator / (Vctor a, double b) {return Vctor(a.x / b, a.y / b);}
double Dot(Vctor a, Vctor b) {return a.x * b.x + a.y * b.y;}
double Cro(Vctor a, Vctor b) {return a.x * b.y - a.y * b.x;}
int Cmp(double x){
  if(fabs(x) < Eps)return 0;
  return x < 0 ? -1 : 1;
}
double Dis(Vctor a) {return sqrt(Dot(a, a));}
double ans;
int n, L, top;
void Samsara(){
  sort(d, d + n);
  int k;
  for(int i = 0; i < n; i++){
    while(top > 1 && Cmp(Cro(_pb[top - 1] - _pb[top - 2], d[i] - _pb[top - 2])) <= 0)top--;
    _pb[top++] = d[i];
  }
  k = top;
  for(int i = n - 2; i >= 0; i--){
    while(top > k && Cmp(Cro(_pb[top - 1] - _pb[top - 2], d[i] - _pb[top - 2])) <= 0)top--;
    _pb[top++] = d[i];
  }
  if(n > 1)top--;
}
int main(){
  scanf("%d%d", &n, &L);
  for(int i = 0; i < n; i++)
    scanf("%lf%lf", &d[i].x, &d[i].y);
  Samsara();
  for(int i = 1; i <= top; i++)
    e[i] = _pb[i] - _pb[i - 1];
  e[top + 1] = _pb[0] - _pb[top];
  for(int i = 1; i <= top + 1; i++)
    ans += Dis(e[i]);
  ans += Pi * L * 2;
  printf("%.0lf\n", ans);
  return 0;
}