首页 > 其他 > 详细

58. Length of Last Word (String)

时间:2016-10-26 07:26:29      阅读:233      评论:0      收藏:0      [点我收藏+]

Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

 

class Solution {
public:
    int lengthOfLastWord(string s) {
        if(s.empty()) return 0;
        
        int len = s.length();
        int i = len - 1;
        int lastLen = 0;
        
        // 去掉空格
        while(s[i] ==   && i>=0){
            --i;
        }//while
        while(i >= 0 && s[i] !=  ){
            ++lastLen;
            --i;
        }//while
        return lastLen;
    }
};

 

58. Length of Last Word (String)

原文:http://www.cnblogs.com/qionglouyuyu/p/5998948.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!